-122=3(1-6k)+1

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Solution for -122=3(1-6k)+1 equation: 



-122=3(1-6k)+1

We move all terms to the left:

-122-(3(1-6k)+1)=0

We add all the numbers together, and all the variables

-(3(-6k+1)+1)-122=0



We calculate terms in parentheses: -(3(-6k+1)+1), so:

3(-6k+1)+1

We multiply parentheses

-18k+3+1

We add all the numbers together, and all the variables

-18k+4

Back to the equation:

-(-18k+4)



We get rid of parentheses

18k-4-122=0

We add all the numbers together, and all the variables

18k-126=0

We move all terms containing k to the left, all other terms to the right

18k=126

k=126/18

k=7

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