3y+10=2(y-4)

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Solution for 3y+10=2(y-4) equation: 



3y+10=2(y-4)

We move all terms to the left:

3y+10-(2(y-4))=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

3y-2y+8+10=0

We add all the numbers together, and all the variables

y+18=0

We move all terms containing y to the left, all other terms to the right

y=-18

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