-11+3(b+5)=6+b

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Solution for -11+3(b+5)=6+b equation: 



-11+3(b+5)=6+b

We move all terms to the left:

-11+3(b+5)-(6+b)=0

We add all the numbers together, and all the variables

3(b+5)-(b+6)-11=0

We multiply parentheses

3b-(b+6)+15-11=0

We get rid of parentheses

3b-b-6+15-11=0

We add all the numbers together, and all the variables

2b-2=0

We move all terms containing b to the left, all other terms to the right

2b=2

b=2/2

b=1

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