(4b+6)(b=4)=0

Solution for (4b+6)(b=4)=0 equation:

(4b+6)(b=4)=0

We move all terms to the left:

(4b+6)(b-(4))=0

We multiply parentheses ..

(+4b^2-16b+6b-24)=0

We get rid of parentheses

4b^2-16b+6b-24=0

We add all the numbers together, and all the variables

4b^2-10b-24=0

a = 4; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·4·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*4}=\frac{-12}{8}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*4}=\frac{32}{8}
=4
$