-11+2x+20=12+3x+-(x+10)+30

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Solution for -11+2x+20=12+3x+-(x+10)+30 equation: 



-11+2x+20=12+3x+-(x+10)+30

We move all terms to the left:

-11+2x+20-(12+3x+-(x+10)+30)=0

We add all the numbers together, and all the variables

2x-(12+3x+-(x+10)+30)+9=0

We use the square of the difference formula

2x-(12+3x-(x+10)+30)+9=0



We calculate terms in parentheses: -(12+3x-(x+10)+30), so:

12+3x-(x+10)+30

determiningTheFunctionDomain
3x-(x+10)+12+30

We add all the numbers together, and all the variables

3x-(x+10)+42

We get rid of parentheses

3x-x-10+42

We add all the numbers together, and all the variables

2x+32

Back to the equation:

-(2x+32)



We get rid of parentheses

2x-2x-32+9=0

We add all the numbers together, and all the variables

-23!=0

There is no solution for this equation

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