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4x+2(x-5)=3(x-4)
We move all terms to the left:
4x+2(x-5)-(3(x-4))=0
We multiply parentheses
4x+2x-(3(x-4))-10=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
6x-(3x-12)-10=0
We get rid of parentheses
6x-3x+12-10=0
We add all the numbers together, and all the variables
3x+2=0
We move all terms containing x to the left, all other terms to the right
3x=-2
x=-2/3
x=-2/3
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