-11+2(4y+3)=8y-5

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Solution for -11+2(4y+3)=8y-5 equation: 



-11+2(4y+3)=8y-5

We move all terms to the left:

-11+2(4y+3)-(8y-5)=0

We multiply parentheses

8y-(8y-5)+6-11=0

We get rid of parentheses

8y-8y+5+6-11=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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