10/2x+6+3/2x+6=7/x-7

Solution for 10/2x+6+3/2x+6=7/x-7 equation:

10/2x+6+3/2x+6=7/x-7

We move all terms to the left:

10/2x+6+3/2x+6-(7/x-7)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x-7)!=0

x∈R


We add all the numbers together, and all the variables

10/2x+3/2x-(7/x-7)+12=0

We get rid of parentheses

10/2x+3/2x-7/x+7+12=0

We calculate fractions


(3x+10)/2x^2+(-14x)/2x^2+7+12=0

We add all the numbers together, and all the variables

(3x+10)/2x^2+(-14x)/2x^2+19=0

We multiply all the terms by the denominator


(3x+10)+(-14x)+19*2x^2=0

Wy multiply elements

38x^2+(3x+10)+(-14x)=0

We get rid of parentheses

38x^2+3x-14x+10=0

We add all the numbers together, and all the variables

38x^2-11x+10=0

a = 38; b = -11; c = +10;
Δ = b2-4ac
Δ = -112-4·38·10
Δ = -1399
Delta is less than zero, so there is no solution for the equation