-11+10(a+10)=4-5(2a+11)

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Solution for -11+10(a+10)=4-5(2a+11) equation: 



-11+10(a+10)=4-5(2a+11)

We move all terms to the left:

-11+10(a+10)-(4-5(2a+11))=0

We multiply parentheses

10a-(4-5(2a+11))+100-11=0



We calculate terms in parentheses: -(4-5(2a+11)), so:

4-5(2a+11)

determiningTheFunctionDomain
-5(2a+11)+4

We multiply parentheses

-10a-55+4

We add all the numbers together, and all the variables

-10a-51

Back to the equation:

-(-10a-51)



We add all the numbers together, and all the variables

10a-(-10a-51)+89=0

We get rid of parentheses

10a+10a+51+89=0

We add all the numbers together, and all the variables

20a+140=0

We move all terms containing a to the left, all other terms to the right

20a=-140

a=-140/20

a=-7

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