5(3-2y)=4y+3(2)

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Solution for 5(3-2y)=4y+3(2) equation: 



5(3-2y)=4y+3(2)

We move all terms to the left:

5(3-2y)-(4y+3(2))=0

We add all the numbers together, and all the variables

5(-2y+3)-(4y+32)=0

We multiply parentheses

-10y-(4y+32)+15=0

We get rid of parentheses

-10y-4y-32+15=0

We add all the numbers together, and all the variables

-14y-17=0

We move all terms containing y to the left, all other terms to the right

-14y=17

y=17/-14

y=-1+3/14

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