-10x2+2x+6=2

Solution for -10x2+2x+6=2 equation:

-10x^2+2x+6=2

We move all terms to the left:

-10x^2+2x+6-(2)=0

We add all the numbers together, and all the variables

-10x^2+2x+4=0

a = -10; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·(-10)·4
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{41}}{2*-10}=\frac{-2-2\sqrt{41}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{41}}{2*-10}=\frac{-2+2\sqrt{41}}{-20}
$