-3y(2y-4)=47

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Solution for -3y(2y-4)=47 equation: 



-3y(2y-4)=47

We move all terms to the left:

-3y(2y-4)-(47)=0

We multiply parentheses

-6y^2+12y-47=0

a = -6; b = 12; c = -47;
Δ = b2-4ac
Δ = 122-4·(-6)·(-47)
Δ = -984
Delta is less than zero, so there is no solution for the equation

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