-10(x-2)+20x=(x+4)-20

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Solution for -10(x-2)+20x=(x+4)-20 equation: 



-10(x-2)+20x=(x+4)-20

We move all terms to the left:

-10(x-2)+20x-((x+4)-20)=0

We add all the numbers together, and all the variables

20x-10(x-2)-((x+4)-20)=0

We multiply parentheses

20x-10x-((x+4)-20)+20=0



We calculate terms in parentheses: -((x+4)-20), so:

(x+4)-20

We get rid of parentheses

x+4-20

We add all the numbers together, and all the variables

x-16

Back to the equation:

-(x-16)



We add all the numbers together, and all the variables

10x-(x-16)+20=0

We get rid of parentheses

10x-x+16+20=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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