-75x2+290x=240

Solution for -75x2+290x=240 equation:

-75x^2+290x=240

We move all terms to the left:

-75x^2+290x-(240)=0

a = -75; b = 290; c = -240;
Δ = b2-4ac
Δ = 2902-4·(-75)·(-240)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(290)-110}{2*-75}=\frac{-400}{-150}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(290)+110}{2*-75}=\frac{-180}{-150}
=1+1/5
$