-10(n+3)=1/2(25-14n)

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Solution for -10(n+3)=1/2(25-14n) equation:



-10(n+3)=1/2(25-14n)
We move all terms to the left:
-10(n+3)-(1/2(25-14n))=0
Domain of the equation: 2(25-14n))!=0
n∈R
We add all the numbers together, and all the variables
-10(n+3)-(1/2(-14n+25))=0
We multiply parentheses
-10n-(1/2(-14n+25))-30=0
We multiply all the terms by the denominator
-10n*2(-14n+25))-(1-30*2(-14n+25))=0
Wy multiply elements
-20n^2(--60n(-=0
We use the square of the difference formula
-20n^2(+60n(-=0

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