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2.4x(x+20)=-6
We move all terms to the left:
2.4x(x+20)-(-6)=0
We add all the numbers together, and all the variables
2.4x(x+20)+6=0
We multiply parentheses
2x^2+40x+6=0
a = 2; b = 40; c = +6;
Δ = b2-4ac
Δ = 402-4·2·6
Δ = 1552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1552}=\sqrt{16*97}=\sqrt{16}*\sqrt{97}=4\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{97}}{2*2}=\frac{-40-4\sqrt{97}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{97}}{2*2}=\frac{-40+4\sqrt{97}}{4} $
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