-10(-y-2)=-2(2y+3)

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Solution for -10(-y-2)=-2(2y+3) equation: 



-10(-y-2)=-2(2y+3)

We move all terms to the left:

-10(-y-2)-(-2(2y+3))=0

We add all the numbers together, and all the variables

-10(-1y-2)-(-2(2y+3))=0

We multiply parentheses

10y-(-2(2y+3))+20=0



We calculate terms in parentheses: -(-2(2y+3)), so:

-2(2y+3)

We multiply parentheses

-4y-6

Back to the equation:

-(-4y-6)



We get rid of parentheses

10y+4y+6+20=0

We add all the numbers together, and all the variables

14y+26=0

We move all terms containing y to the left, all other terms to the right

14y=-26

y=-26/14

y=-1+6/7

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