(3x+1)/4=(5-2x)/3

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Solution for (3x+1)/4=(5-2x)/3 equation: 



(3x+1)/4=(5-2x)/3

We move all terms to the left:

(3x+1)/4-((5-2x)/3)=0

We add all the numbers together, and all the variables

(3x+1)/4-((-2x+5)/3)=0

We calculate fractions


3x/()+(-((-2x+5)*4)/()=0



We calculate terms in parentheses: +(-((-2x+5)*4)/(), so:

-((-2x+5)*4)/(

We multiply all the terms by the denominator


-((-2x+5)*4)



We calculate terms in parentheses: -((-2x+5)*4), so:

(-2x+5)*4

We multiply parentheses

-8x+20

Back to the equation:

-(-8x+20)



We get rid of parentheses

8x-20

Back to the equation:

+(8x-20)



We get rid of parentheses

3x/()+8x-20=0

We multiply all the terms by the denominator


3x+8x*()-20*()=0

We add all the numbers together, and all the variables

3x+8x*()=0

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