-1/9(x-27)+3(x+3)=x+67

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Solution for -1/9(x-27)+3(x+3)=x+67 equation:



-1/9(x-27)+3(x+3)=x+67
We move all terms to the left:
-1/9(x-27)+3(x+3)-(x+67)=0
Domain of the equation: 9(x-27)!=0
x∈R
We multiply parentheses
-1/9(x-27)+3x-(x+67)+9=0
We get rid of parentheses
-1/9(x-27)+3x-x-67+9=0
We multiply all the terms by the denominator
3x*9(x-27)-x*9(x-27)-67*9(x-27)+9*9(x-27)-1=0
Wy multiply elements
27x^2(x-9x^2(x-603x(x+81x(x-1=0

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