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2x-12x+10=20(-x+1)/2
We move all terms to the left:
2x-12x+10-(20(-x+1)/2)=0
We add all the numbers together, and all the variables
2x-12x-(20(-1x+1)/2)+10=0
We add all the numbers together, and all the variables
-10x-(20(-1x+1)/2)+10=0
We multiply all the terms by the denominator
-10x*2)-(20(-1x+1)+10*2)=0
We add all the numbers together, and all the variables
-10x*2)-(20(-1x+1)=0
Wy multiply elements
-20x^2=0
a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-40}=0$
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