-1/6f-2/3f=650.

Solution for -1/6f-2/3f=650. equation:

-1/6f-2/3f=650.

We move all terms to the left:

-1/6f-2/3f-(650.)=0


Domain of the equation: 6f!=0

f!=0/6

f!=0

f∈R



Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R


We add all the numbers together, and all the variables

-1/6f-2/3f-650=0

We calculate fractions


(-3f)/18f^2+(-12f)/18f^2-650=0

We multiply all the terms by the denominator


(-3f)+(-12f)-650*18f^2=0

Wy multiply elements

-11700f^2+(-3f)+(-12f)=0

We get rid of parentheses

-11700f^2-3f-12f=0

We add all the numbers together, and all the variables

-11700f^2-15f=0

a = -11700; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-11700)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-11700}=\frac{0}{-23400}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-11700}=\frac{30}{-23400}
=-1/780
$