-1/5(y+3)=2/3(y-5)

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Solution for -1/5(y+3)=2/3(y-5) equation: 



-1/5(y+3)=2/3(y-5)

We move all terms to the left:

-1/5(y+3)-(2/3(y-5))=0



Domain of the equation: 5(y+3)!=0

y∈R





Domain of the equation: 3(y-5))!=0

y∈R



We calculate fractions


(-3yy/(5(y+3)*3(y-5)))+(-10yy/(5(y+3)*3(y-5)))=0



We calculate terms in parentheses: +(-3yy/(5(y+3)*3(y-5))), so:

-3yy/(5(y+3)*3(y-5))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)





We calculate terms in parentheses: +(-10yy/(5(y+3)*3(y-5))), so:

-10yy/(5(y+3)*3(y-5))

We multiply all the terms by the denominator


-10yy

Back to the equation:

+(-10yy)



We get rid of parentheses

-3yy-10yy=0

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