-1/4(-c-1)=-1/12(2c-3)

Solution for -1/4(-c-1)=-1/12(2c-3) equation:

-1/4(-c-1)=-1/12(2c-3)

We move all terms to the left:

-1/4(-c-1)-(-1/12(2c-3))=0


Domain of the equation: 4(-c-1)!=0

c∈R



Domain of the equation: 12(2c-3))!=0

c∈R


We add all the numbers together, and all the variables

-1/4(-1c-1)-(-1/12(2c-3))=0

We calculate fractions


(-12c2/(4(-1c-1)*12(2c-3)))+(-(-4c0)/(4(-1c-1)*12(2c-3)))=0


We calculate terms in parentheses: +(-12c2/(4(-1c-1)*12(2c-3))), so:

-12c2/(4(-1c-1)*12(2c-3))

We multiply all the terms by the denominator


-12c2

We add all the numbers together, and all the variables

-12c^2

Back to the equation:

+(-12c^2)



We calculate terms in parentheses: +(-(-4c0)/(4(-1c-1)*12(2c-3))), so:

-(-4c0)/(4(-1c-1)*12(2c-3))

We add all the numbers together, and all the variables

-(-4c)/(4(-1c-1)*12(2c-3))

We multiply all the terms by the denominator


-(-4c)

We get rid of parentheses

4c

Back to the equation:

+(4c)


We get rid of parentheses

-12c^2+4c=0

a = -12; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-12)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-12}=\frac{-8}{-24}
=1/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-12}=\frac{0}{-24}
=0
$