7(p+1)=5(p-2)

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Solution for 7(p+1)=5(p-2) equation: 



7(p+1)=5(p-2)

We move all terms to the left:

7(p+1)-(5(p-2))=0

We multiply parentheses

7p-(5(p-2))+7=0



We calculate terms in parentheses: -(5(p-2)), so:

5(p-2)

We multiply parentheses

5p-10

Back to the equation:

-(5p-10)



We get rid of parentheses

7p-5p+10+7=0

We add all the numbers together, and all the variables

2p+17=0

We move all terms containing p to the left, all other terms to the right

2p=-17

p=-17/2

p=-8+1/2

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