-1/3(a-4)=-1/6(-5a+5)-a

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Solution for -1/3(a-4)=-1/6(-5a+5)-a equation: 



-1/3(a-4)=-1/6(-5a+5)-a

We move all terms to the left:

-1/3(a-4)-(-1/6(-5a+5)-a)=0



Domain of the equation: 3(a-4)!=0

a∈R





Domain of the equation: 6(-5a+5)-a)!=0

a∈R



We calculate fractions


6a^2/(3(a-4)*6(-5a+5)-a))+(-(-3aa)/(3(a-4)*6(-5a+5)-a))=0



We calculate terms in parentheses: -(-3aa)/(3(a-4)*6(-5a+5)-a)), so:

-3aa)/(3(a-4)*6(-5a+5)-a)

We multiply all the terms by the denominator


-3aa)-a)*(3(a-5a-4)*6(+5)

We add all the numbers together, and all the variables

-3aa)-a)*(3(-4a-4)*65

We add all the numbers together, and all the variables

-4a-3aa)-a)*(3(

Back to the equation:

-(-4a-3aa)-a)*(3()



We get rid of parentheses

6a^2/(3(a-4)*6(-5a+5)-a))+(+4a+3aa-a)*(3()=0

We multiply all the terms by the denominator


6a^2+4a*(3(a-4)*6(-5a+5)-a))+(+3aa*(3(a-4)*6(-5a+5)-a))+(-a*(3())*(3(a-4)*6(-5a+5)-a))+(=0

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