3(r+3)-6=12

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Solution for 3(r+3)-6=12 equation: 



3(r+3)-6=12

We move all terms to the left:

3(r+3)-6-(12)=0

We add all the numbers together, and all the variables

3(r+3)-18=0

We multiply parentheses

3r+9-18=0

We add all the numbers together, and all the variables

3r-9=0

We move all terms containing r to the left, all other terms to the right

3r=9

r=9/3

r=3

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