-1/2x+6x-2=10

Solution for -1/2x+6x-2=10 equation:

-1/2x+6x-2=10

We move all terms to the left:

-1/2x+6x-2-(10)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

6x-1/2x-12=0

We multiply all the terms by the denominator


6x*2x-12*2x-1=0

Wy multiply elements

12x^2-24x-1=0

a = 12; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·12·(-1)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{39}}{2*12}=\frac{24-4\sqrt{39}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{39}}{2*12}=\frac{24+4\sqrt{39}}{24}
$