-1/2(12c-8)+4c=-2(c-2)

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Solution for -1/2(12c-8)+4c=-2(c-2) equation: 



-1/2(12c-8)+4c=-2(c-2)

We move all terms to the left:

-1/2(12c-8)+4c-(-2(c-2))=0



Domain of the equation: 2(12c-8)!=0

c∈R



We add all the numbers together, and all the variables

4c-1/2(12c-8)-(-2(c-2))=0

We multiply all the terms by the denominator


4c*2(12c-8)-((-2(c-2)))*2(12c-8)-1=0



We calculate terms in parentheses: -((-2(c-2)))*2(12c-8), so:

(-2(c-2)))*2(12c-8



Wy multiply elements

8c^2(1-((-2(c-2)))*2(12c-8)-1=0

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