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9y^2+16-24y=0
a = 9; b = -24; c = +16;
Δ = b2-4ac
Δ = -242-4·9·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{24}{18}=1+1/3$
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