-1/2(10y-2)+3=14

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Solution for -1/2(10y-2)+3=14 equation: 



-1/2(10y-2)+3=14

We move all terms to the left:

-1/2(10y-2)+3-(14)=0



Domain of the equation: 2(10y-2)!=0

y∈R



We add all the numbers together, and all the variables

-1/2(10y-2)-11=0

We multiply all the terms by the denominator


-11*2(10y-2)-1=0

Wy multiply elements

-22y(1-1=0

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