4(2y-1)=32

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Solution for 4(2y-1)=32 equation: 



4(2y-1)=32

We move all terms to the left:

4(2y-1)-(32)=0

We multiply parentheses

8y-4-32=0

We add all the numbers together, and all the variables

8y-36=0

We move all terms containing y to the left, all other terms to the right

8y=36

y=36/8

y=4+1/2

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