-1/2(10x-20)=1/3(9x-18)

Solution for -1/2(10x-20)=1/3(9x-18) equation:

-1/2(10x-20)=1/3(9x-18)

We move all terms to the left:

-1/2(10x-20)-(1/3(9x-18))=0


Domain of the equation: 2(10x-20)!=0

x∈R



Domain of the equation: 3(9x-18))!=0

x∈R


We calculate fractions


(-3x9/(2(10x-20)*3(9x-18)))+(-2x1/(2(10x-20)*3(9x-18)))=0


We calculate terms in parentheses: +(-3x9/(2(10x-20)*3(9x-18))), so:

-3x9/(2(10x-20)*3(9x-18))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9