-1(x-12)+3(x+2)=6x+162

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Solution for -1(x-12)+3(x+2)=6x+162 equation: 



-1(x-12)+3(x+2)=6x+162

We move all terms to the left:

-1(x-12)+3(x+2)-(6x+162)=0

We multiply parentheses

-1(x-12)+3x-(6x+162)+6=0

We get rid of parentheses

-1(x-12)+3x-6x-162+6=0

We add all the numbers together, and all the variables

-3x-1(x-12)-156=0

We move all terms containing x to the left, all other terms to the right

-3x-1(x-12)=156

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