13(x+1)=3(x-13)+12

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Solution for 13(x+1)=3(x-13)+12 equation: 



13(x+1)=3(x-13)+12

We move all terms to the left:

13(x+1)-(3(x-13)+12)=0

We multiply parentheses

13x-(3(x-13)+12)+13=0



We calculate terms in parentheses: -(3(x-13)+12), so:

3(x-13)+12

We multiply parentheses

3x-39+12

We add all the numbers together, and all the variables

3x-27

Back to the equation:

-(3x-27)



We get rid of parentheses

13x-3x+27+13=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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