-1(1+4m)=3(2-m)+4

Solution for -1(1+4m)=3(2-m)+4 equation:

-1(1+4m)=3(2-m)+4

We move all terms to the left:

-1(1+4m)-(3(2-m)+4)=0

We add all the numbers together, and all the variables

-1(4m+1)-(3(-1m+2)+4)=0


We calculate terms in parentheses: -(3(-1m+2)+4), so:

3(-1m+2)+4

We multiply parentheses

-3m+6+4

We add all the numbers together, and all the variables

-3m+10

Back to the equation:

-(-3m+10)


We get rid of parentheses

-1(4m+1)+3m-10=0

We add all the numbers together, and all the variables

3m-1(4m+1)-10=0

We move all terms containing m to the left, all other terms to the right

3m-1(4m+1)=10