-(x-8)+4x=2(3/2+8)+x

Solution for -(x-8)+4x=2(3/2+8)+x equation:

-(x-8)+4x=2(3/2+8)+x

We move all terms to the left:

-(x-8)+4x-(2(3/2+8)+x)=0


Domain of the equation: 2+8)+x)!=0

We move all terms containing x to the left, all other terms to the right

8)+x)!=-2

x!=-2/1

x!=-2

x∈R


We add all the numbers together, and all the variables

4x-(x-8)-(2(3/2+8)+x)=0

We get rid of parentheses

4x-x-(2(3/2+8)+x)+8=0

We multiply all the terms by the denominator


4x*2+8)+x)-x*2+8)+x)-(2(3+8*2+8)+x)=0

We add all the numbers together, and all the variables

4x*2+8)+x)-x*2+8)+x)-(227+x)=0

Wy multiply elements

8x+8)+x)-x*2+8)+x)-(227+x)=0

We add all the numbers together, and all the variables

8x+8)+x)-x*2+8)+x)-(x+227)=0