(x+2)/4=(3-x)/8

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Solution for (x+2)/4=(3-x)/8 equation: 



(x+2)/4=(3-x)/8

We move all terms to the left:

(x+2)/4-((3-x)/8)=0

We add all the numbers together, and all the variables

(x+2)/4-((-1x+3)/8)=0

We calculate fractions


x/()+(-((-1x+3)*4)/()=0



We calculate terms in parentheses: +(-((-1x+3)*4)/(), so:

-((-1x+3)*4)/(

We multiply all the terms by the denominator


-((-1x+3)*4)



We calculate terms in parentheses: -((-1x+3)*4), so:

(-1x+3)*4

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)



We get rid of parentheses

4x-12

Back to the equation:

+(4x-12)



We get rid of parentheses

x/()+4x-12=0

We multiply all the terms by the denominator


x+4x*()-12*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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