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5+2/3y=y+2
We move all terms to the left:
5+2/3y-(y+2)=0
Domain of the equation: 3y!=0We get rid of parentheses
y!=0/3
y!=0
y∈R
2/3y-y-2+5=0
We multiply all the terms by the denominator
-y*3y-2*3y+5*3y+2=0
Wy multiply elements
-3y^2-6y+15y+2=0
We add all the numbers together, and all the variables
-3y^2+9y+2=0
a = -3; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·(-3)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*-3}=\frac{-9-\sqrt{105}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*-3}=\frac{-9+\sqrt{105}}{-6} $
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