-(x+3)+2(x+4)=3x-2

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Solution for -(x+3)+2(x+4)=3x-2 equation: 



-(x+3)+2(x+4)=3x-2

We move all terms to the left:

-(x+3)+2(x+4)-(3x-2)=0

We multiply parentheses

-(x+3)+2x-(3x-2)+8=0

We get rid of parentheses

-x+2x-3x-3+2+8=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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