(x+3)/3-(4x-1)/6=3+(x/3)

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Solution for (x+3)/3-(4x-1)/6=3+(x/3) equation: 



(x+3)/3-(4x-1)/6=3+(x/3)

We move all terms to the left:

(x+3)/3-(4x-1)/6-(3+(x/3))=0

We add all the numbers together, and all the variables

(x+3)/3-(4x-1)/6-(3+(+x/3))=0

We calculate fractions


(6x+18)/()+(-4x)/()+(-(3+(+x*6)/()=0



We calculate terms in parentheses: +(-(3+(+x*6)/(), so:

-(3+(+x*6)/(

We multiply all the terms by the denominator


-(3+(+x*6)



We calculate terms in parentheses: -(3+(+x*6), so:

3+(+x*6

determiningTheFunctionDomain
(+x*6+3

Back to the equation:

-((+x*6+3)



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