-(n-2)=-2(n+3)

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Solution for -(n-2)=-2(n+3) equation: 



-(n-2)=-2(n+3)

We move all terms to the left:

-(n-2)-(-2(n+3))=0

We get rid of parentheses

-n-(-2(n+3))+2=0



We calculate terms in parentheses: -(-2(n+3)), so:

-2(n+3)

We multiply parentheses

-2n-6

Back to the equation:

-(-2n-6)



We add all the numbers together, and all the variables

-1n-(-2n-6)+2=0

We get rid of parentheses

-1n+2n+6+2=0

We add all the numbers together, and all the variables

n+8=0

We move all terms containing n to the left, all other terms to the right

n=-8

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