4(d+4)+12=20

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Solution for 4(d+4)+12=20 equation: 



4(d+4)+12=20

We move all terms to the left:

4(d+4)+12-(20)=0

We add all the numbers together, and all the variables

4(d+4)-8=0

We multiply parentheses

4d+16-8=0

We add all the numbers together, and all the variables

4d+8=0

We move all terms containing d to the left, all other terms to the right

4d=-8

d=-8/4

d=-2

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