-(n-12)+4(2n+3)=38

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Solution for -(n-12)+4(2n+3)=38 equation: 



-(n-12)+4(2n+3)=38

We move all terms to the left:

-(n-12)+4(2n+3)-(38)=0

We multiply parentheses

-(n-12)+8n+12-38=0

We get rid of parentheses

-n+8n+12+12-38=0

We add all the numbers together, and all the variables

7n-14=0

We move all terms containing n to the left, all other terms to the right

7n=14

n=14/7

n=2

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