3b-(6-b)=-228b

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Solution for 3b-(6-b)=-228b equation: 



3b-(6-b)=-228b

We move all terms to the left:

3b-(6-b)-(-228b)=0

We add all the numbers together, and all the variables

3b-(-1b+6)-(-228b)=0

We get rid of parentheses

3b+1b+228b-6=0

We add all the numbers together, and all the variables

232b-6=0

We move all terms containing b to the left, all other terms to the right

232b=6

b=6/232

b=3/116

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