-(j+2)=3

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Solution for -(j+2)=3 equation: 



-(j+2)=3

We move all terms to the left:

-(j+2)-(3)=0

We get rid of parentheses

-j-2-3=0

We add all the numbers together, and all the variables

-1j-5=0

We move all terms containing j to the left, all other terms to the right

-j=5

j=5/-1

j=-5

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