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980x^2-210x+8=0
a = 980; b = -210; c = +8;
Δ = b2-4ac
Δ = -2102-4·980·8
Δ = 12740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12740}=\sqrt{196*65}=\sqrt{196}*\sqrt{65}=14\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-14\sqrt{65}}{2*980}=\frac{210-14\sqrt{65}}{1960} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+14\sqrt{65}}{2*980}=\frac{210+14\sqrt{65}}{1960} $
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