-(a-7)-4(a+2)=3-5a+a-5

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Solution for -(a-7)-4(a+2)=3-5a+a-5 equation: 



-(a-7)-4(a+2)=3-5a+a-5

We move all terms to the left:

-(a-7)-4(a+2)-(3-5a+a-5)=0

We add all the numbers together, and all the variables

-(a-7)-4(a+2)-(-4a-2)=0

We multiply parentheses

-(a-7)-4a-(-4a-2)-8=0

We get rid of parentheses

-a-4a+4a+7+2-8=0

We add all the numbers together, and all the variables

-1a+1=0

We move all terms containing a to the left, all other terms to the right

-a=-1

a=-1/-1

a=1

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