6(2y+3)=11y+18

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Solution for 6(2y+3)=11y+18 equation: 



6(2y+3)=11y+18

We move all terms to the left:

6(2y+3)-(11y+18)=0

We multiply parentheses

12y-(11y+18)+18=0

We get rid of parentheses

12y-11y-18+18=0

We add all the numbers together, and all the variables

y=0

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