-(a+2)+(8a-4)/2=8

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Solution for -(a+2)+(8a-4)/2=8 equation:



-(a+2)+(8a-4)/2=8
We move all terms to the left:
-(a+2)+(8a-4)/2-(8)=0
We get rid of parentheses
-a+(8a-4)/2-2-8=0
We multiply all the terms by the denominator
-a*2+(8a-4)-2*2-8*2=0
We add all the numbers together, and all the variables
-a*2+(8a-4)-20=0
Wy multiply elements
-2a+(8a-4)-20=0
We get rid of parentheses
-2a+8a-4-20=0
We add all the numbers together, and all the variables
6a-24=0
We move all terms containing a to the left, all other terms to the right
6a=24
a=24/6
a=4

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