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-5/2x-6=-1-4-6x
We move all terms to the left:
-5/2x-6-(-1-4-6x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-5/2x-(-6x-5)-6=0
We get rid of parentheses
-5/2x+6x+5-6=0
We multiply all the terms by the denominator
6x*2x+5*2x-6*2x-5=0
Wy multiply elements
12x^2+10x-12x-5=0
We add all the numbers together, and all the variables
12x^2-2x-5=0
a = 12; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·12·(-5)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{61}}{2*12}=\frac{2-2\sqrt{61}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{61}}{2*12}=\frac{2+2\sqrt{61}}{24} $
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